0.1x^2-x+2.5=0

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Solution for 0.1x^2-x+2.5=0 equation: 



0.1x^2-x+2.5=0

We add all the numbers together, and all the variables

0.1x^2-1x+2.5=0

a = 0.1; b = -1; c = +2.5;
Δ = b2-4ac
Δ = -12-4·0.1·2.5
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{1}{0.2}=5$

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